Solutions for Molarity Problems

     [85.0g NaCl] [1 mol NaCl] [1 L    ]   =   1.45 mol/dm³  = 1.45 M
     [ 1 L            ] [58.5 g NaCl][1 dm³]

2) What is the molarity of 1 dm³ of solution containing 765 g of C₆H₁₂O₆?

     [765 g C₆H₁₂O₆] [1 mol C₆H₁₂O₆     ] =   4.24 mol/dm³  = 4.24 M
     [ 1 dm³                ] [180.1 g C₆H₁₂O₆]

3) What is the molarity of 350.0 mL of solution containing 37.0g of HCl?

     [37.0g HCl] [1 mol HCl] [1000 mL]    =   0.003 mol/dm³  = 0.003 M
     [ 350.0 mL][36.5 g HCl][1 dm³       ]

4) What is the molarity of 500.0 cm³ of solution containing 49.6 g of H₃BO₃?

     [49.6 g H₃BO₃] [1 mol H₃BO₃     ] [1000 cm³] =   1.6 mol/dm³  = 1.6 M
     [ 500.0 cm³     ] [61.8  g H₃BO₃  ] [1 dm³        ]

5) What is the concentration of 35.0 mL of solution containing 29.4 g FeCl₂?

     [29.4 g FeCl₂] [1 mol FeCl₂   ][1000 mL]    =   6.62 mol/dm³  = 6.62 M
     [ 35.0 mL      ][126.8 g FeCl₂][1 dm³      ]

6) How would you prepare 735mL of a 1.5M solution of  KPO₄?

     [735 mL][1 dm³       ][1.5 mol  KPO₄][133.9 g KPO₄]    =  147.6 g KPO₄
                    [1000 mL][ 1 dm³                 ][1 mol KPO₄     ]

     Dissolve 147.6 g KPO₄ in enough water to make 735 mL of solution.

7) How would you prepare 25.0 cm³ of a 2.0 M solution of NaOH?    

    [25.0 cm³][1 dm³       ][2.0 mol  NaOH][39.9 g NaOH]    =  2.00 g NaOH
                     [1000 cm³][ 1 dm³                    ][1 mol NaOH ]

     Dissolve 2.0 g NaOH in enough water to make 25.0 cm³ of solution.

8) How would you prepare 1.5 L of a 1.2 M solution of  KIO₃?

     [1.5 L][1 dm³][1.2 mol  KIO₃][39.9 g KIO₃]    =  214 g KIO₃
                [1L     ][ 1 dm³                    ][1 mol KIO₃ ]

     Dissolve 214 g KIO₃ in enough water to make 1.5 L of solution.

9) How would you prepare 1.5 dm³ of a 0.50 M solution of AgNO₃?    

     [1.5 dm³][0.50 mol  AgNO₃][169.9 g AgNO₃]    =  127 g AgNO₃
                    [ 1 dm³                       ][1 mol AgNO₃    ]

     Dissolve 127 g KIO₃ in enough water to make 1.5 dm³ of solution.

10) How would you prepare 125 cm³ of a 1.3 M solution of Mg(ClO₃)₂?     

     [125 cm³][1 dm³        ][1.3 mol  Mg(ClO₃)₂][189.9 g Mg(ClO₃)₂]    =  30.9 g Mg(ClO₃)₂
                     [1000 cm³][ 1 dm³                      ][1 mol MgClO₃   ]

     Dissolve 17.5 g MgClO₃ in enough water to make 125 cm³ of solution.